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4=5x^2-x
We move all terms to the left:
4-(5x^2-x)=0
We get rid of parentheses
-5x^2+x+4=0
a = -5; b = 1; c = +4;
Δ = b2-4ac
Δ = 12-4·(-5)·4
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-9}{2*-5}=\frac{-10}{-10} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+9}{2*-5}=\frac{8}{-10} =-4/5 $
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